Data Interpretation - Tabular Practice Set

Q. (1-5)   Study the given table carefully to answer the following questions.


Field Name
Shape
Side (in m)
Base (in m)
Height (in m)
Radius (in m)
Cost of flooring (in Rs. per sq. metre)
Cost of fencing (in Rs. per m)
   A
Triangle

16
12

50
20
   B
Rectangle
10 × 20



30
15
   C
Square
15



40
18
   D
Parallelogram

20
12

60
25
   E
Circle



10
45
22


Q1.  What is the cost of flooring of A?
                 a) Rs.4000                   b) Rs.4600                   c) Rs.4800
                 d) Rs.5000                   e) Rs.4400

Q2.What is the difference between the cost of fencing of C and that of B?
                a) Rs.180                     b) Rs.120                     c) Rs.240
                d) Rs.360                     e) Rs.480

Q3.  What is the ratio of the cost of flooring to that of fencing of field D?
               a) 4 : 1                         b) 6 : 1                         c) 8 : 1
               d) 9 : 1                         e) 5 : 1

Q4. The cost of fencing of field E is approximately what percent of the cost of flooring of field C?
             a) 10.5%                      b) 19.46%                    c) 18.71%
             d) 15.36%                    e) 13.82%

Q5. The cost of fencing of field C is what percent of the cost of fencing of field D?
            a) 87.54%                    b) 67.5%                      c) 72.13%
            d) 54.36%                    e) 46.5%

==>> Must read - Data Interpretation Guide

Solution

1.      Option C

A is a triangle
                  So, area of A =  1/2 × 16 × 12 = 96 sqm
                  So, cost of flooring of A = 96 × 50 = Rs.4800

2.      Option A

Perimeter of B = 2 (10 + 20) = 60 m
                  So, cost of fencing of B = 60 × 15 = 900
                  Perimeter of C = 4 × 15 = 60 m
                  So, cost of fencing of C = 60 × 18 = Rs.1080
                  So, required difference = 1080 - 900 = Rs.180

3.      Option D

Area of D = Base × Height
= 20 × 12 = 240m2
                So, cost of flooring of D= 240 × 60 = Rs.14400
                Perimeter of D = 2 (20 + 12) = 64 m
    So, cost of fencing of D = 64 × 25 = Rs.1600      
                So, required ratio = 14400 : 1600 = 9 : 1

4.      Option D

Perimeter of E = 2πr = 2 × 22 / 7 × 10 = 440 / 7 m
                  Cost of fencing of E =  440 / 7 × 22 = Rs.1382.85
                  Area of C = (15)2 = 225m2
                  So, cost of flooring of C = 225 × 40 = Rs.9000
                  So, required % = 1382.85 × 100 / 9000
                 = 15.36% of flooring cost of C.

5.      Option B

Fencing cost of C = Rs.1080
                  Fencing cost of D = Rs.1600
Required % =  1080 / 1600 × 100 = 67.5%
RBI Grade B Online Classes by Ramandeep Singh - Join here

Join 40,000+ readers and get free notes in your email

0 comments:

Post a Comment

Thanks for commenting. It's very difficult to answer every query here, it's better to post your query on IBPSToday.com