Compound Interest is an important chapter for banking exams. In every exams, you will find at least 1 question in every exam. From last 4 years I am analyzing the papers of various exams. I noticed that few questions are repeating in all the exams.

(a) Rs. 482

(b) Rs. 424

(c) Rs. 842

(d) Rs. 512

(a) 4%

(b) 5%

(c) 3%

(d) 8%

Now dividing the second equation by the first equation , we get :

Substituting this value of (1+ R/100 )3 in the first equation we get : 3p/2 = 6,690

∴ Required sum = Rs. 4,460.

[ Note : The sum is 2 times in 4 years ; it will be 8 ( i.e. 23 ) times in 4 x 3 years i.e. 12 years ]

=> the least possible value of n is 4.

Hence, the least number of years required is 4.

### Ques 1.

What is the time in which Rs 2000 will amount to Rs. 2420 at 10% per annum compound interest?### Ques 2.

What sum will become Rs. 6,690 after three years and Rs. 10,035 after six years on compound interest ?### Ques 3.

The difference between the compound interest and the simple interest on a certain sum at 5% per annum for 2 years is Rs. 1.50. Find the sum.### Ques 4.

Compound interest on a certain sum for 2 years at 10% p.a . is Rs 420. What would be the simple interest at the same rate and for the same time.### Ques 5.

A sum of money placed at compound interest doubles itself in 4 years . In how many years will it amount to eight times itself ?### Ques 6.

Find the least number of complete years in which a sum of money put at 25% p.a. compound interest will be more than double itself .### Ques 7.

Divide Rs. 3903 between A and B , so That when compound annually A's share at the end of 7 years may be equal to B's share at the end of 9 years . The rate of interest is given to be 4% per annum.### Ques 8.

How much more would Rs. 20,000 fetch , after two years , if it is put at 20 % p.a. . Compound interest payable half yearly than if it is put at 20% p.a. compound interest payable yearly ?(a) Rs. 482

(b) Rs. 424

(c) Rs. 842

(d) Rs. 512

### Ques 9.

A sum in invested at compound interest payable annually . The interest in two successive years is Rs. 225 and Rs. 236.25. Th rate of interest is(a) 4%

(b) 5%

(c) 3%

(d) 8%

### solutions :

**Ans 1.****Ans 2**.Now dividing the second equation by the first equation , we get :

Substituting this value of (1+ R/100 )3 in the first equation we get : 3p/2 = 6,690

∴ Required sum = Rs. 4,460.

**Ans 3.****Ans 4.**

**Ans 5.**

**Hence , the sum will be 8 times itself in 12 years .**

[ Note : The sum is 2 times in 4 years ; it will be 8 ( i.e. 23 ) times in 4 x 3 years i.e. 12 years ]

**Ans 6.**

=> the least possible value of n is 4.

Hence, the least number of years required is 4.

**Ans 7.**

**Ans 8.**

**Ans 9.**5%

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