Today I am going to share 2 Data Interpretation sets.

### Set 1

Study the following table carefully and answer the questions given below:
Number of boys of standard xi participating in different games

- Every student (boy or girl) of each class of standard XI participates in a game.
- In each class, the number of girls participating in each game is 25% of the number of boys participating in each game.
- Each student (boy or girl) participates in one and only one game.

**Solution:**Total number of boys in XI D = 40

Number of girls in XI D = 25% of 40 = 10

Since all the boys of XI D passed, so the number of boys in XII D = 40

Ratio of boys & girls in XII D is 5: 1

Number of girls in XII D = 1/5 ×40=8

∴number of girls who failed = (10 – 8) = 2

**Solution:**

Total number of boys playing Chess & Badminton = (32 + 52) = 84

Number of girls playing Hockey & Football = 25% of 84

= 1/4 ×84=21

Since 84: 21 is 4: 1, so the girls playing hockey and football are combined to yield a ratio of boys to girls as 4: 1.

So, Hockey and Football is the correct answer.

**Solution:**Number of boys in XI A = 44

Number of girls in XI B = 25% of 48 = 12

Number of girls in XI C = 25% of 48 = 12

(44 + 12 + 12) = 68

Let x be the total number of students.

Then 25% of x = 68

Or, x = (68 × 100)/25 =272

Total number of students in the school = 272.

**Solution:**

4 times the number of girls in XI B & XI C = 4 (12 + 12) = 96.

**Solution:**Number of boys in XI E = 4

Number of girls in XI B playing Table tennis = 25% of 16 = 4

Number of girls in XI C playing Hockey = 25% of 8 = 2

(4 + 4 + 2) = 10

Total number of students

(228 + 25% of 228) = 285

Let x% of 285 = 10

Or, x = (10 × 100)/285 =3.51

Total number of students getting advantage approximately is 3.51.

**Solution:**

Since the number of girls = 25% of the number of boys, so only 25% of the boys can participate in social work

**Study the table carefully and answer the questions given below:**

## Set 2

**Financial Statement of A Company Over The Years (Rupees in Lakhs)**

**Solution:**1984-85

only a look is needed (can be studied in the table).

**Solution:**We look at the ‘Net profit’ and ‘Profits before Interest and Depreciation’. We need to find the year in which ‘profits before……..’ is the smallest multiple of ‘Net Profits’. Use approximations, 38 ÷ 1, 40 ÷ 2, 52 ÷ 5, 60 ÷ 6.5, 80÷20, 92 ÷ 22 and make quick mental calculation. Obviously any one of the last two is the answer. We have 80 ÷20=4,92 ÷22>4,and hence 80 ÷20 is the minimum.

Hence, 1984 – 85 is the answer.

**Solution:**Mental calculation with approximation is sufficient. Among 2700 - 2500, 900 – 800, 600 – 500, 99 – 92 and 220 – 212, the fourth is a single digit figure and it is the least.

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