Missing DI Practice Set for IBPS PO: Part 7

(Direction 1 -5) Following is a tabulation of the number of books published by six different publishers on different categories of books. Read the table carefully and answer the questions.
Books Category
A
B
C
D
E
F
Total
Comics
500
560
430
555
450
620
-
Science & Tech
-
492
326
200
-
340
-
Story
120
-
-
220
230
330
-
Magazines
545
-
312
210
110
-
1955
Literature
444
480
310
-
475
360
-
Competitive Exam
975
-
350
-
700
650
3495
Total
2964
2765
2038
1800
-
2750

Question 1.

Approximately what is the average number of science & tech book published by all the publishers?

A.320
B. 330
C. 335
D. 338
E. None of these

Question 2. 

What is the ratio between number of magazines published by publisher F to the number of story books published by publisher B, If number of competitive exam books published by E is 7 times more than book published by D?

A. 90: 35
B. 90:37
C. 35:90
D. 37:90
E. None of these

Question 3. 

Total number of books published by A and C is what percentage more or less than total number of comics and competitive exam books published?

A. 35%
B. 34%
C. 24%
D. 20%
E. None of these

Question 4.

The total number of story books published by C forms what percentage of the total number of comics books published?

A. 10 %
B. 14 %
C.15%
D. 18%
E. None of these

Question 5. 

If the total number of story books and magazines are equal then what will be the difference between story books published by B and number of Literature books published by E and F together?

A. 60
B. 70
C. 80
D. 90
E. None of these

Answers:

1. Option D

→ Science and tech books published by A = 2964 – 2584 = 380
→  Science and tech books published by E = 2255 – 1965 = 290
→  Avg. number of science & tech books published by all publishers =(380 + 492+ 326+ 200 + 290 + 340)/6 = 338 (ans)

2. Option B

→  Number of magazines published by F =
→  2750 – [620+340+330+360+650] =450
→  Number of magazines published by B =
→  1955 – [545+312+210+110+ 450] = 328
→  Given: no. of competitive exam books by E = 7 * no. of competitive books by D
→  700 = 7 * no. of cometitive books by D
→  No. of competitive books by D= 100
→  No. of competitive exam books by D = 100
→  No. of competitive exam books by B = 3495- [975+350+100+700+650] = 720
→  No. of story books published by B = 2765- [ 560+492+328+480+720] = 185
→  Ratio = Magazine by F : Magazine by  = 450 : 185 = 90: 37

3. Option C

→  Total no. of books published by A & C = 2964 + 2038 = 5002
→  Total no. of comics & competitive exam books published = 3115 + 3495 = 6610
→  Less percentage = [(6610 -5002)/ 6610] * 100 = 16080/661 = 24 %

4. Option A

→  Percentage = (310 * 100)/ 3115 = 10%

5. Option D

→ Story books published by B = 1955- [120+310+220+230+330] = 745
→  Literature books published by E and F = 475 + 360 = 835
→  Difference = 835 – 745 = 90

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