New Student Offer - HELLO

Join Here

Quant Mania: Quadratic Inequality (with Detailed Solution)

Published on Tuesday, February 09, 2016
Dear Readers,
Today we are presenting you Quant Mania on Quadratic Inequality which is very important for your upcoming LIC AAO and other exams. You may expect same questions in your upcoming exams. Try to solve it.

Quadratic Inequality

Directions (Q. 1-5): In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer.

1. I. x2 – 25 = 0, II. y2 – 3y - 18 = 0
a) if x > y
b) if x ≥ y
c) if x < y
d) if x ≤ y
e) if x = y or no relation can be established between x and y.
2. I. 2x2 – 3x + 1 = 0, II. 2y2 - 9y + 9 = 0
a) if x > y
b) if x ≥ y
c) if x < y
d) if x ≤ y
e) if x = y or no relation can be established between x and y.

3. I. x2 = 4y, II. y = (729)1/3
a) if x > y
b) if x ≥ y
c) if x < y
d) if x ≤ y
e) if x = y or no relation can be established between x and y.

4. x2 – 5x + 6 = 0, II. y2 - 3y + 2 = 0
a) if x > y
b) if x ≥ y
c) if x < y
d) if x ≤ y
e) if x = y or no relation can be established between x and y.

5. I. 3x2 – 19x + 20=0, II. (3y – 4) (y – 5) = 0
a) if x > y
b) if x ≥ y
c) if x < y
d) if x ≤ y
e) if x = y or no relation can be established between x and y.

Answers with Solution

1. e;
I. x2 – 25 = 0
or, x2 = 25
or, x = ± 5

II. y2 – 3y - 18 = 0
or, y2 - 6y + 3y - 18= 0
or, y(y - 6) + 3(y - 6) = 0
or, (y - 6) (y + 3) = 0
or, y = 6, -3
Hence, no relation can be established.

2. c;
I. 2x2 – 3x + 1 = 0
or, 2x2 – 2x - 1x + 1 = 0
or, 2x(x – 1) - 1(x - 1) = 0
or, (2x – 1) (x - 1) = 0
x = ½, 1

II. 2y2 - 9y + 9 = 0
or, 2y2 - 6y - 3y + 9 = 0
or, 2y(y - 3) - 3(y - 3) = 0
or, (2y - 3) (y - 3) = 0
y = 3/2, 3
Hence, x < y

3. c;
II. y = (729)1/3
y = 9


I. x2 = 4y
or, x2 = 4 * 9 = 36
or, x = ±6
Hence, 
x < y

4. b;
I. x2 – 5x + 6 = 0
or, x2 – 3x - 2x + 6 = 0
or. x(x - 3) - 2(x – 3) = 0
or, (x - 3) (x - 2) = 0
x = 3, 2

II. y2 - 3y + 2 = 0
or, y2 - 2y - y + 2 = 0
or, y(y - 2) - 1(y - 2) = 0
or, (y - 2) (y - 1) = 0
y = 1, 2
Hence, x ≥ y

5. e;
I. 3x2 – 19x + 20 = 0,
or, 3x2 – 15x – 4x+ 20 = 0
or, 3x(x – 5) – 4(x – 5) = 0
or, (3x – 4) (x – 5) = 0
x = 4/3, 5

II. (3y – 4) (y – 5) = 0
y = 4/3, 5
Hence, x = y


Thanks.
ebook store

About Me

Ramandeep Singh

Ramandeep Singh - Educator

I'm Ramandeep Singh, your guide to banking and insurance exams. With 14 years of experience and over 5000 successful selections, I understand the path to success firsthand, having transitioned from Dena Bank and SBI. I'm passionate about helping you achieve your banking and insurance dreams.

  • Follow me:
Close Menu
Close Menu