# Time and Distance Problems with Solutions

Time and Distance is an important chapter of quantitative aptitude. In every numerical ability exam at least one question can seen related to this chapter. Before solving questions below read Time and Distance concepts.

### This post is a part of Quantitative Aptitude preparation series

1.
How many minutes Raman will take to cover a distance of 400 meters if he runs at a speed of 20 km/hr ?
• A.
2 mins
• C.
1⅕ mins
• E.
1.5 mins
• B.
2.5 mins
• D.
None of these
Explanation :
⇒ Raman's speed = 20 km/hr = 20 × 5/18 = 50/9 m/sec
⇒ 400 × 9/50 = 1⅕ mins

2.
John travelled from his town to city.  John went to city by bicycle at the speed of 25 km/h and came back at the speed of 4 km/h. If John took 5 hours and 48 min to complete his journey, what is the distance between town and city ?
• A.
15 km
• C.
20 km
• B.
22 km
• D.
25 km

Explanation :
⇒ Average speed of John = 2xy/x+y =  2 × 25 × 4 / 25 + 4= 200/29 km/h
⇒ Distance traveled = Speed × Time = 200/29 × 29/5 = 40 Km
⇒ Distance between city and town = 40/2 = 20 km

3.
Speed of a train is 20 meters per second. It can cross a pole in 10 seconds. What is the length of train ?
• A.
150 m
• C.
200 m
• B.
250 m
• D.
300 m
Explanation :
⇒ Lenght of train = 20 × 10 = 200 meters

4.
Ram walks at a speed of  12 km/h. Today the day was very hot so walked at ⅚ of his average speed. He arrived his school 10 minutes late. Find the usual time he takes to cover distance between his school and home ?
• A.
40 mins
• C.
50 mins
• B.
45 mins
• D.
60 mins

Explanation :
⇒ If Ram is walking at ⅚  of his usual speed that means he is taking 6/5 of using time.
⇒ 6/5 of usual time - usual time = 10 mins
⇒ 1/5 of usual time = 10 mins
⇒ Usual time = 50 mins

5.
A car running at 65 km/h takes one hour to cover a distance. If the speed is reduced by 15 km/hour then in how much time it will cover the distance  ?
• A.
72 mins
• C.
76 mins
• B.
78 mins
• D.
None of these

Explanation :
⇒Reduced speed = 65-15 = 50 km/h
⇒ Now car will take 65/50 × 60 mins = 78 mins

6.
In a 100 m race A runs at a speed of 1.66 m/s. If A gives a start of 4m to B and still beats him by 12 seconds. What is the speed of B  ?
• A.
1 m/s
• C.
1.25 m/s
• B.
1.33 m/s
• D.
Rs 1.5 m/s

Explanation :
⇒Time taken by A to cover 100 meters = 60 seconds
⇒ Since A gives a start of 4 seconds then time takes by B = 72 seconds
⇒ B takes 72 seconds to cover 96 meters
⇒ Speed of B = 96/72 = 1.33 m/s

7.
In a kilometer race, A beats B by 100 meters. B beats C by 100 meters. By how much meters does A beat C in the same race ?
• A.
200 meters
• C.
190 meters
• B.
180 meters
• D.
210 meters

Explanation :
⇒ While A covers 1000 meters, B can cover 900 meters
⇒ While B covers 1000 meters, C can cover 900 meters
⇒ Lets assume that all three of them are running same race. So when B runs 900 meters, C can run 900 × 9/10 =810
⇒ So A can beat C by 190 meters.

Smart Prep Kit for Banking Exams by Ramandeep Singh - Download here

### Oliveboard Test Series(Recommended)

#### Bank Exams Today Notes

1. is the 5 th question is for additional time

1. Sorry unable to understand your question :(

2. 5th question..... a car running at 65km/hr take one hour to complete the distance means the distance covered by the car is 65km... k na then speed reduced by 15km/h means the speed of the car is 50km/hr . so the car running at 50km/h take 65/50 hrs to complete the distance i.e., 65 kms

1. Just answer this in how much time a car can cover 65 km by moving at a speed of 50km/h
It is 1.3 hours or 78 minutes

3. Can u please explain the 7th question.... ?

1. Detailed solution is provided. What else I can do.
Just assume that all three people are running in the same race.

4. In 7th question there is written that B beat C by 100 meters than why you are taking 90 meters than why you are assuming.Please reply...

1. When B runs 1000 m C runs 900 m
Now B runs only 900 m there for C take

900 * 900
-------------- meters = 810 meters
1000
Hence C lags by 1000 - 810 = 190 meters

5. last urstion is out of box

1. Really?? You did not understood?? please calm your mind and use a little unitary method then you will understand that when B runs 900m then C will run 810m so if they are running same race then C is lagged by 190m behind by A