Data Interpretation Set - Radar Graph

As many of you might know that I have started Data Interpretation Preparation Series for upcoming exams. In this series, today I am providing Radar Graph questions set.

Use the given data to answer the following questions.

Grade	Rate/Tonne
1	Rs.75,000
2	Rs.60,000

1.   What is the difference between the average sales of grade 1 and 2 in all 4 companies?
a. 5 tonnes
b. 10 tonnes
c. 15 tonnes
d. 20 tonnes
e. 25 tonnes

2. What is the difference between the total income of companies C and A?
a. Rs. 1.05 million
b. Rs. 10.05 million
c. Rs.1005 million
d. Rs. 1.05 crores
e. Rs. 10.05 crores

3. In how many companies is the production of grade 2 tea at least 50% more than that of grade 1?
a. 0
b. 1
c. 2
d. 3
e. 4

4. What percentage of the net income of company A is constituted by grade 1 tea?
a. 50%
b. 33.33%
c. 25%
d. 40%
e. 38.46%

5. Total production by company D is what percentage of that of company B?
a. 140%
b. 150%
c. 160%
d. 170%
e. 180%

Solution: 1.c 2.a 3.d 4.e 5.d

1. Average sales of grade 1= (20+40+50+60)/4= 42.5 tonnes
Average sales of grade 2= (40+60+20+110)/4= 57.5 tonnes
Difference= 57.5-42.5= 15 tonnes.

2. Total income of companies A= (75000*20) + (60000*40) = Rs.3900000
Total income of companies C= (75000*50) + (60000*20) = Rs.4950000

Difference= Rs.1050000= Rs. 1.05 million.

3. 3 companies= A, B and D. See the table below.

Company Grade 1 (tonnes) Grade 2 (tonnes) A 20 40 B 40 60 C 50 20 D 60 110

4. Net income of company A= (75000*20)+(40*60000)= Rs.3900000
  Grade 1 constitutes 38.46% ((150000/3900000)*100)

5. Total production by company D= 60+110= 170 tonnes
Total production by company B= 40+60= 100 tonnes
Total production by company D is 170 % that of company B. (170/100)*100