Data Interpretation - Tabular Practice Set

Q. (1-5): Study the given table carefully to answer the following questions.

Field Name Shape Side (in m) Base (in m) Height (in m) Radius (in m) Cost of flooring (in Rs. per sq. metre) Cost of fencing (in Rs. per m)

A

Triangle

16

12

50

20

B

Rectangle

10 × 20

30

15

C

Square

15

40

18

D

Parallelogram

20

12

60

25

E

Circle

10

45

22

Q1. What is the cost of flooring of A?
a) Rs.4000
b) Rs.4600
c) Rs.4800
d) Rs.5000
e) Rs.4400

Q2.What is the difference between the cost of fencing of C and that of B?
a) Rs.180
b) Rs.120
c) Rs.240
d) Rs.360
e) Rs.480

Q3. What is the ratio of the cost of flooring to that of fencing of field D?
a) 4 : 1
b) 6 : 1
c) 8 : 1
d) 9 : 1
e) 5 : 1

Q4. The cost of fencing of field E is approximately what percent of the cost of flooring of field C?
a) 10.5%
b) 19.46%
c) 18.71%
d) 15.36%
e) 13.82%

Q5. The cost of fencing of field C is what percent of the cost of fencing of field D?
a) 87.54%
b) 67.5%
c) 72.13%
d) 54.36%
e) 46.5% 

==>> Must read - Data Interpretation Guide

Solution

1. Option C 
A is a triangle
So, area of A = 1/2 × 16 × 12 = 96 m2
So, cost of flooring of A = 96 × 50 = Rs.4800

2. Option A 
Perimeter of B = 2 (10 + 20) = 60 m
So, cost of fencing of B = 60 × 15 = 900
Perimeter of C = 4 × 15 = 60 m
So, cost of fencing of C = 60 × 18 = Rs.1080
So, required difference = 1080 - 900 = Rs.180

3. Option D
Area of D = Base × Height
= 20 × 12 = 240m2
So, cost of flooring of D= 240 × 60 = Rs.14400
Perimeter of D = 2 (20 + 12) = 64 m
So, cost of fencing of D = 64 × 25 = Rs.1600
So, required ratio = 14400 : 1600 = 9 : 1

4. Option D
Perimeter of E = 2πr = 2 × 22 / 7 × 10 = 440 / 7 m
Cost of fencing of E = 440 / 7 × 22 = Rs.1382.85
Area of C = (15)2= 225m2
So, cost of flooring of C = 225 × 40 = Rs.9000
So, required % = 1382.85 × 100 / 9000
= 15.36% of flooring cost of C.

5. Option B
Fencing cost of C = Rs.1080
Fencing cost of D = Rs.1600
Required % = 1080 / 1600 × 100 = 67.5%
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