Data Interpretation - Tabular Practice Set

Q. (1-5): Study the given table carefully to answer the following questions.

Field Name	Shape	Side (in m)	Base (in m)	Height (in m)	Radius (in m)	Cost of flooring (in Rs. per sq. metre)	Cost of fencing (in Rs. per m)
A	Triangle		16	12		50	20
B	Rectangle	10 × 20				30	15
C	Square	15				40	18
D	Parallelogram		20	12		60	25
E	Circle				10	45	22

Q1. What is the cost of flooring of A?
a) Rs.4000
b) Rs.4600
c) Rs.4800
d) Rs.5000
e) Rs.4400

Q2.What is the difference between the cost of fencing of C and that of B?
a) Rs.180
b) Rs.120
c) Rs.240
d) Rs.360
e) Rs.480

Q3. What is the ratio of the cost of flooring to that of fencing of field D?
a) 4 : 1
b) 6 : 1
c) 8 : 1
d) 9 : 1
e) 5 : 1

Q4. The cost of fencing of field E is approximately what percent of the cost of flooring of field C?
a) 10.5%
b) 19.46%
c) 18.71%
d) 15.36%
e) 13.82%

Q5. The cost of fencing of field C is what percent of the cost of fencing of field D?
a) 87.54%
b) 67.5%
c) 72.13%
d) 54.36%
e) 46.5%

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Solution

1. Option C 

A is a triangle
So, area of A = 1/2 × 16 × 12 = 96 m²
So, cost of flooring of A = 96 × 50 = Rs.4800

2. Option A 

Perimeter of B = 2 (10 + 20) = 60 m
So, cost of fencing of B = 60 × 15 = 900
Perimeter of C = 4 × 15 = 60 m
So, cost of fencing of C = 60 × 18 = Rs.1080
So, required difference = 1080 - 900 = Rs.180

3. Option D
Area of D = Base × Height
= 20 × 12 = 240m²
So, cost of flooring of D= 240 × 60 = Rs.14400
Perimeter of D = 2 (20 + 12) = 64 m
So, cost of fencing of D = 64 × 25 = Rs.1600
So, required ratio = 14400 : 1600 = 9 : 1

4. Option D
Perimeter of E = 2πr = 2 × 22 / 7 × 10 = 440 / 7 m
Cost of fencing of E = 440 / 7 × 22 = Rs.1382.85
Area of C = (15)²= 225m²
So, cost of flooring of C = 225 × 40 = Rs.9000
So, required % = 1382.85 × 100 / 9000
= 15.36% of flooring cost of C.

5. Option B
Fencing cost of C = Rs.1080
Fencing cost of D = Rs.1600
Required % = 1080 / 1600 × 100 = 67.5%