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Number Series Practice Questions - 2 Sets

Published on Monday, November 23, 2015
Today we are sharing some question based on series. Try to solve these questions and share your marks. Keep Practicing.
number series

SET 1

QUESTIONS

 In each of the following questions, a number series is given with one term missing. Choose the
correct alternative that will continue the same pattern and replace the question mark in given series.

1) 120, 99, 80, 63, 48, ?
a) 35
b) 38
c) 39
d) 40
e) None of these

2) 0.5, 0.55, 0.65, 0.8, ?
a) 0.9
b) 0.82
c) 1
d) 0.95
e) None of these

3) 5, 6, 9, 15, ?, 40
a) 21
b) 25
c) 27
d) 33
e) None of these
4) 1, 1, 4, 8, 9, 27, 16, ?
a) 32
b) 64
c) 81
d) 256
e) None of these

5) 240, ?, 120, 40, 10, 2
a) 180
b) 240
c) 420
d) 480
e) None of these

6) 4, 6, 9, 13 ½ , ?
a) 17 ½
b) 19
c) 20 ¼
d) 22 ¾
e) None of these

7) 1, 2, 3, 6, 9, 18, ?, 54
a) 18
b) 27
c) 36
d) 81
e) None of these

8) 2, 3, 3, 5, 10, 13, ?, 43, 172, 177
a) 23
b) 38
c) 39
d) 40
e) None of these

9) 2, 2, 5, 13, 28, ?
a) 49
b) 50
c) 51
d) 52
e) None of these

10) 2, 7, 27, 107, 427, ?
a) 1262
b) 1707
c) 4027
d) 4207
e) None of these

ANSWERS WITH SOLUTIONS

1) Option – a
Pattern => -21, -19, -17, -15, .......
So missing term is 35

2) Option – c
Pattern => +0.05, +0.10, +0.15, ......
So missing term is 0.8 + 0.20 = 1

3) Option – b
Pattern => +1, +3, +6......i.e. +1, +(1+2), +(1+2+3),  ....
So missing term is 15 + ( 1+2+3+4 ) = 25

4) Option – b
Pattern => 1^2 , 1^3, 2^2, 2^3, 2^2, 3^3, ....
So missing term is 4^3 = 64

5) Option – b
Pattern => ÷1, ÷2, ÷3, ÷4, .....
So missing term is 240 ÷ 1 = 240

6) Option – c
Pattern => × 3/2
So missing term is 13 ½ × 3/2 = 27/2 × 3/2 = 20 ¼

7) Option – b
Pattern => ×2, × 3/2, × 2, × 3/2, ×2, ...
So missing term is 18 × 3/2 = 27

8) Option – c
Pattern => +1, ×1, +2, ×2, +3, ×3, ....
So missing term is 13 × 3 = 39

9) Option – d
Pattern => +0, +3, +8, +15, ... i.e. +(1^2-1), +(2^2 -1), +(3^2 -1), ...
So missing term is 28 + (5^2 – 1) = 28 + 24 = 52

10) Option – b
Pattern =>+5, +20, +80, +320, .... i.e. +(5 × 1^2), + (5 × 2^2), +(5 × 4^2), ....
So missing term is 427 + (5 × 16^2) = 427 + 1280 = 1707

Set 2

QUESTIONS 

In each of the following questions, one term in the number series is wrong. Find out the wrong term.

1) 2, 5, 10, 17, 26, 37, 50, 64
a) 17
b) 26
c) 37
d) 64
e) None of these

2) 10, 26, 74, 218, 654, 1946, 5834
a) 26
b) 74
c) 218
d) 654
e) None of these

3) 1, 3, 12, 25, 48
a) 3
b) 12
c) 25
d) 48
e) None of these

4) 1, 5, 9, 15, 25, 37, 49
a) 9
b) 15
c) 25
d) 37
e) None of these

5) 0, 2, 3, 5, 8, 10, 15, 18, 24, 26, 35
a) 18
b) 24
c) 28
d) 10
e) None of these

ANSWERS WITH SOLUTIONS

1) Options – d
Pattern => (1^2  + 1) , (2^2 + 1), (3^2 + 1), (4^2 + 1), ....
Wrong Term = 64
Right Term = 8 ^ 2  +  1 = 65

2) Options – d
Pattern => ×2 + 1, ×3 + 1, ×2 + 1, ×3 + 1,....
Wrong Term = 654
Right Term = 218 × 3 – 4 = 650

3) Options – c
Pattern => (1^2 – 0^2), (2^2 – 1^2), (4^2 – 2^2), ....
Wrong Term =25
Right Term = (6 ^2 – 3 ^2) = 27

4) Options – b
Pattern => 1^2, (2^2 + 1), 3^2, (4^2 +1), 5^2, (6^2 + 1), 7^2
Wrong Term = 15
Right Term = (4^2 + 1) = 17

5) Options – a
Pattern => Its combination of two series
I. 0, 3, 8, 15, 24, 35; and
II. 2, 5, 10, 18, 26
Pattern of both series = +3, +5, +7, +9,...
Wrong in II series = 18
Right = (10 + 7) = 17

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