Quant Mania: Approximation - Part 2

Published on Saturday, January 23, 2016
Dear Readers,
Today we are presenting the third session of Quant Mania which is based on Approximation. These are very important for your tomorrow's SIDBI Grade A Exam and other upcoming exams. Solve it and please share your valuable views about our new initiative under the platform "Mania Session".

Quant Mania: Approximation

Directions (Q. 1-10): What approximate value should come in place of the question mark (?) in the following questions?

1. 20.02 × 13.97 – 21.989 × 4.97 ÷ (4)0 = ?
a) 140
b) 150
c) 160
d) 170
e) None of these

2. 175 % of 27.50 + 1.25% of 120 = ?
a) 48
b) 50
c) 52
d) 54
e) None of these

3. (1494.89 ÷ 5.005 + 0.996) ÷ 11.990 = ?
a) 20
b) 25
c) 28
d) 30
e) None of these

4. (149.95)3 = ? × 105
a) 32.25
b) 35.50
c) 33.75
d) 37.25
e) None of these

5. (38.0599 ×〖10〗^2)/380.6 × √1935.96 × 1.501 = 11 × ?
a) 30
b) 40
c) 50
d) 60
e) None of these

6. 499.01 + 306 ×13.009 = ?
a) 4278
b) 4478
c) 3478
d) 4488
e) None of these

7. 〖(10005.66)〗^2/10004.001 × √3256 × 1.0001 = ? 〖(10005.66)〗^2/10004.001
a) 570456
b) 600000
c) 650000
d) 570856
e) None of these

8. (199.99999)3 = ?
a) 1600000
b) 800000
c) 4000000
d) 8000000
e) None of these

9. 2070.01 ÷ 12.00 + 29.991 × (3.999)2  = ?
a) 753
b) 553
c) 653
d) 683
e) 636

10. (86)2 ÷ ∛29791 = ?
a) 186
b) 240
c) 139
d) 140
e) 320

Answers

1. d 
2. b 
3. b 
4. c 
5. d 
6. e 
7. c 
8. d 
9. e 
10. c

Can I help you?

ramandeep singh

Hey I am Ramandeep Singh. I am determined to help students preparing for RBI, SEBI, NABARD and IBPS exams. Do you want me to help you ?

Join my class here
    Follow me:
Close Menu
Close Menu