Hi readers,
Today I am sharing Missing Table set, this type of DI set is trending in the exams. Solve now :-
Direction :-
But 40% of the students were females.
∴ Total no. of students = (100/40 x 32) = 80
No. of male students = ( 80-32) = 48
∴ No. of male students who were average
=(1/3 x 48)= 16
Today I am sharing Missing Table set, this type of DI set is trending in the exams. Solve now :-
Direction :-
A professor keeps data on students tabulated by performance and sex of the student. The data are kept on a computer disk but, unfortunately, some of them are lost because of a virus.Only the following could be recovered:
Panic buttons were pressed but of no avail. An expert committee was formed,which decided that the following facts were self -evident :
(a) Half the students were either excellent or good
(b) 40% of the students were females
(c) One third of the male students were average
1. How many students are both female and excellent?
(a) 0
(b) 8
(c) 16
(d) 32
2.What proportion of good students are male?
(a) 0
(b) 0.25
(c) 0.4
(d) 1.0
3. What proportion of female students are good ?
(a) 0
(b) 0.25
(c) 0.5
(d) 1.0
4. How many students are both and good?
(a) 10
(b) 16
(c) 22
(d) 48
5.Among average students, what is the ratio of male to female?
(a) 1 : 2
(b) 2 : 1
(c) 3 : 2
(d) 2 : 3
Solutions :
24___28 : First complete the table with the help of the facts provided as shown below:
No. of females = 32
No. of male students = ( 80-32) = 48
∴ No. of male students who were average
=(1/3 x 48)= 16
1. No. of students who are both female and excellent = none.
2. Proportion of female students who are male
3. Proportion of female students who are good
4. No.of students who are both male and good = 22.
5. Among average students, the ratio of male of female = 16: 24 = 2:3.
Must read
Data Interpretation Guide
