The following tables shows the net interest earnings and interest expenses of some banks for years 2003-2004 and 2004-2005:
Question 1:
Question 2:
Question 3:
b) Exactly three banks have an increase in interest earnings during the year 2004-2005 over the previous year between 5% and 10%
c) Total deposits in the five banks during the year 2004-2005 amount to less than Rs. 160 billions.
d) None of these
Directions for question 4 to 6: Refer to the data below and answer the questions that follow.
The sports club in the university organized three major games viz: football, volleyball and basketball. The ratio of the number of students playing football and basketball only and those playing volleyball and basketball only is 2:3. The students playing all the three games are twice the number of students playing football and volleyball only. The numbers of students playing only basketball are 20 less than seven times the number of playing both football and basketball only. The difference in the number of students playing only football and those playing only volleyball is one more than the number of students playing football and volleyball only. The number of students playing all the three games is three more than the number of students playing volleyball and basketball only. Total number of students playing exactly two games is 112.
Question 4:
Question 5:
Question 6:
Directions for question (7 - 9): Refer to the data below and answer the questions that follow.
Seven positive numbers P,Q, R ,S,T,U and V arranged in ascending order. Also
(i) The first four numbers are in arithmetic progression.
(ii) The last four numbers are in geometric progression
(iii) P/S , P/ Q , U/S are in increasing arithmetic progression and each of them is greater than 1
(iv) Common difference of the above A.P. ( in iii ) is the same as the common ratio of numbers in geometric progression.
(v) There are two numbers between Q and P
(vi) T is the smallest and R is the greatest the value of R is 1080.
(vii) S is equidistant from Q and U in the arrangement.
Question 7:
Question 8
Question 9
Question 10
b) 30
c) 10
d) 40
e) 20
e) All of these
Answers With Explanation
Solution 1
Punjab bank , bank returns during 2004-2005 = 7485/4361 = 1.72bank returns during 2003-2004 = 6647/4353 =1.53
Therefore ,
(a) The percentage increase = 12.6 % approx
Solution 2
10% hike in rate of Interest must have increased interest earnings by 10% than the earnings with interest rate before hike
It is sufficient to compare the earnings without hike which are equal to 100 / 110 *earnings during 2004- 2005
(D) Three banks have shown a decrease in loans offered.
Solution 3
Minimum interest rate charged by any bank = 11%
Maximum loan offered by banks = 21744 * 100/11 < Rs.200000 mn
Hence statement I is false.
b) Only Andhra bank has increased in interest earnings between 5% and 10% In the year 2004-2005
Statement (b) is false
c)Total interest expenses during 2004 – 2005 = Rs. 13603
Maximum interest rate on deposits = 8.5 %
Minimum deposits in 5 banks = 13603 * 100 /8.5
8001*20 > Rs.1600000 mn
Statement ( c ) is false
Hence (d) none of these
Solution 4-6
Let the number of students playing football and basketball only be 2y. so the number of students playing volleyball and basketball only is 3yThe number of students playing basketball only is 14y – 20
Let the number of students playing football and volleyball only be x. so , the number of students playing all the three games is 2x
Now ,
2x = 3y +3
(2x/3 – 1 ) = y
X+2y +3y = 112
X+10x / 3 - 5 = 112
Thus we get x =27 and y = 17
The number of students playing only basketball = 14y – 20 = 218 hence
(b) is the right answer for Question 4
Let the number of students playing football be ‘a’ and those playing volleyball be ‘b’
a-b = x+1 = 28 ….. (1)
a+b = 366 ……………(2)
solving equation (1) and (2) weget ,
a=197 and b=169
Hence ( c ) is the right answer for Question 5
The number of students playing all the three games is 2x = 54 and those playing only football and basketball is 2y= 34
Solution 7 - 9
From (iii) and (iv)P>S , P >Q , U >S
P/S < P/Q and P/S < U/S
Gives S > Q and U> P
Using (v) , (vi) and (vii) we get the following arrangement ,
T<Q<V<S<P<U<R
So T , Q , V , and S are AP, while S , P , U and R in GP
From (ii) and (iii),
R/U = U/P = P/S = P/Q - P/S = U/S – P/Q ……… ( i )
P/Q = 2P /S and U/S = 3P/S
U = 3P
U/P = 3
So the common ratio of the geometric progression is 3
R=1080 , U= 360 , P= 120 AND S= 40
Substituting values of P and S in equation (i)
120/Q – 3 = 3
Q=20
T= 10 , G= 20 and V = 30
The required arrangement is 10 , 20 , 30 , 40 , 120 , 360 , 1080
Solution 10
Which gives n = 10