__Directions (1 to 5):__Following Line Graph represents the uniform speed of Trains (A, B, C, D and E) on two different days in meter per second and the Bar Chart represents the length of each train in meter.

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**1. Approximately what is the average time taken by train D on day 1 and day 2 to cross the platform of length 500 meter?**

A. 6 Sec

B. 9 Sec

C. 12 Sec

D. Data Insufficient

E. None of these

**2. At what speed must train C travel on Day 2 such that it crosses the platform of 500 meter in half of the expected time?**

A. 139 m/s

B.149 m/s

C. 159 m/s

D. Data insufficient

E. None of these

**3. What is the average speed of all the trains on Day 1 in Km/Hr?**

A. 449

B. 459

C. 429

D. Data insufficient

E. None of these

**4. What will be the total time travelled by train B, C & D on Day 1?**

A. 554 minutes

B. 224 minutes

C. 334 minutes

D. Data insufficient

E. None of these

**5. What is the ratio of Percentage increase or decrease in speed of Train A from day 1 to day 2 to Train D from day 1 to day 2?**

A. 4:1

B. 3:1

C. 2:1

D. Data insufficient

E. None of these

## Answers:

#### 1. Option B

Time= Distance/Speed

Time taken on day 1, t1= (train length + Platform Length)/speed

= (225+500)/200

= 3.6 sec

Time taken on day 2, t2= (train length + Platform Length)/speed

= (225+500)/50

= 14.5 sec

Average time = (t1+t2)/2

= 9 seconds (ans)

#### 2. Option A

Expected time = (125+500)/ 70

= 9 seconds

Speed needed to cross the platform in 4.5 sec = (125+ 500)/4.5

= 139 m/s (ans)

#### 3. Option E

Average speed on day 1 = total speed/5

= (60+75+105+200+170)/5

= 610/5

= 122 m/s

Average speed on day 1 in km/hr = 122*(18/5)

= 439 km/hr (ans)

#### 4. Option D

Without knowing the distance travelled time cannot be calculated, so data is not sufficient.

#### 5. Option C

% increase in speed of Train A= [(150-60)/60]*100

= 150 %

% decrease in speed of Train D= [(200-50)/200]*100

= 75 %

Ratio = 150: 75

= 2: 1(ans)

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