Some values are missing. Answer the questions on the basis of given table and information in question.
Person
|
Speed
|
Time
|
|---|---|---|
Suhail
|
60 km/h
|
300 min.
|
Sunil
|
-
|
-
|
Saurabh
|
-
|
4 hour
|
Sanjay
|
-
|
-
|
Sumit
|
50 km/h
|
-
|
Question.1
If the time taken by Sunil is 3 hours more than that of Suhail to cover the given distance and the ratio of the distance between Sunil and Sanjay is 7:4, find the Suhail’s Speed.A. 55 km/h
B. 62 km/h
C. 87.5 km/h
D. 72.5 km/h
E. None of these
Ans. C.
Solution:
Question.2
With the help of question 1 Find the average speed of Sunil and Suhail.A. 73.75 km/h
B. 62 km/h
C. 50 km/h
D. 76.92 km/h
E. 75 km/h
Ans.D.
Solution:
Question.3
Sumit is going to Delhi with a speed of x km/h. Delhi is 384 km far from his house. If the time is taken by him as same as to travel 324 km with the speed of 15m/s. Find the value of x.A. 50 km/h
B. 64 km/h
C. 75 km/h
D. 80 km/h
E. 52.5 km/h
Ans. B.
Solution:
According to the question:
Time is taken by Sumit to cover the distance of 384 km with the speed of x = Time taken by Sumit to cover the distance of 324 km with the speed of 15 m/s.
Question.4
If the difference between the speed of Saurabh and Sanjay is 55 km/h and time taken by both is 14 km to cover the given distance. What will be time taken by Sanjay to cover the distance of 250 km.A. 6.25 hour
B. 5 hour
C. 5.25 hour
D. 7.5 hour
E. None of these
Ans. A.
Solution:
= 95km/h.
Time taken by Saurabh is given that is 4 hours.
So time taken by Sanjay is 10 hours.
If the Speed is 95+55 = 150 km/h
Then distance = 150×10 = 1500 km.
But this is not possible because the distance travel by Sunil and Sanjay is 1100 km.
If the distance is 95-55 = 40 km/h
Then distance = 40×10 = 400 km.
So the speed is 40 km/h
Time taken to cover the distance of 250 km =
250/40= 6.25 hour
Question.5
Find the ratio of the speed between Saurabh and Sumit.A. 11:8
B. 10:19
C. 15:7
D. 8:11
E. 19:10
Ans. E.
Solution:
