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# Data Interpretation Practice Questions - Missing Figures Tables

In a series to provide practice question sets for Data Interpretation section, Today I am providing two practice sets.

### Must read

Study the given table carefully to answer the following questions.

Field Name
Shape
Side (in m)
Base (in m)
Height (in m)
Radius (in m)
Cost of flooring (in Rs. per sq. metre)
Cost of fencing (in Rs. per m)
A
Triangle

16
12

50
20
B
Rectangle
10 × 20

30
15
C
Square
15

40
18
D
Parallelogram

20
12

60
25
E
Circle

10
45
22

1) What is the cost of flooring of A?
a) Rs.4000                   b) Rs.4600                   c) Rs.4800
d) Rs.5000                   e) Rs.4400

2) What is the difference between the cost of fencing of C and that of B?
a) Rs.180                     b) Rs.120                     c) Rs.240
d) Rs.360                     e) Rs.480

3) What is the ratio of the cost of flooring to that of fencing of field D?
a) 4 : 1                         b) 6 : 1                         c) 8 : 1
d) 9 : 1                         e) 5 : 1

4) The cost of fencing of field E is approximately what percent of the cost of flooring of field C?
a) 10.5%                      b) 19.46%                    c) 18.71%
d) 15.36%                    e) 13.82%

5) The cost of fencing of field C is what percent of the cost of fencing of field D?
a) 87.54%                    b) 67.5%                      c) 72.13%
d) 54.36%                    e) 46.5%

Study the given chart carefully and answer the following questions.

Train A

Station
Arrival time
Departure time
Distance from origin (in km)
Number of passengers boarding at each station
Fare (in Rs.)
Ahmedabad
Starting
5:00 pm
--
400
--
Vadodara
6:30 pm
6:35 pm
100
100
50
Bharuch
8:50 pm
9:00 pm
250
90
120
Mumbai
4:00 am
4:10 am
800
300
400
Pune
7:30 am
7:45 am
1050
150
500
Solapur
10:20 am
Terminates
1280
--
620

Train B

Station
Arrival time
Departure time
Distance from origin
Number of passengers boarding at each station
Fare (in Rs.)
Solapur
Starting
6:00 pm
--
300
--
Pune
7:40 pm
7:45 pm
230
150
120
Mumbai
9:30 pm
9:35 pm
480
270
220
Bharuch
5:40 am
5:55 am
1030
50
500
Vadodara
9:00 am
9:10 am
1180
100
570
Ahmedabad
12:00 noon
Terminates
1280
--
620

6) The number of passengers boarding Train A at Vadodara is what percent of the number of passengers boarding Train B at Mumbai?
a) 37.03%                    b) 47.03%                                c) 27.03%
d) 47.30%                    e) None of these

7) What is the difference between the speed of Train A and that of Train B?
a) 2.73 kmph               b) 1.97 kmph                           c) 3.6 kmph
d) 2.62 kmph               e) 3.9 kmph

8) What is the ratio of the total passengers of Train A to that of Train B?
a) 102 : 79                   b) 104 : 87                               c) 103 : 87
d) 110 : 79                   e) 113 : 87

9) The total income of Train A is what percent of the total income of Train B?
a) 180%                       b) 159.51%                              c) 123.29%
d) 125%                       e) 127.64%

10) If the average speed of Train A increases by 10% then when will it reach to its destination?
a) 7:45 am                   b) 9:45 am                               c) 8:45 am
d) 10:45 am                 e) 11:45 am

### Solutions

1. Option C
A is a triangle
So, area of A = 1/2 × 16 × 12 = 96 sqm
So, cost of flooring of A = 96 × 50 = Rs.4800

2. Option A
Perimeter of B = 2 (10 + 20) = 60 m
So, cost of fencing of B = 60 × 15 = 900
Perimeter of C = 4 × 15 = 60 m
So, cost of fencing of C = 60 × 18 = Rs.1080
So, required difference = 1080 ⎯ 900 = Rs.180

3. Option D
Area of D = Base × Height
= 20 × 12 = 240 mtr sq
So, cost of flooring of D= 240 × 60 = Rs.14400
Perimeter of D = 2 (20 + 12) = 64 m
So, cost of fencing of D = 64 × 25 = Rs.1600
So, required ratio = 14400 : 1600 = 9 : 1

4. Option D
Perimeter of E = 2πr = 2 × 22/7 × 10 = 440/7 m
Cost of fencing of E = 440/7 × 22 = Rs.1382.85
Area of C = 15 * 15= 225 mtr square
So, cost of flooring of C = 225 × 40 = Rs.9000
So, required % = 1382.85 x 100 / 9000
= 15.36% of flooring cost of C.
5. Option B
Fencing cost of C = Rs.1080
Fencing cost of D = Rs.1600
Required % = 1080/1600 × 100 = 67.5%

6. Option A
Required percentage = 100/270 × 100 = 37.03%

7. Option A
Speed of Train A = 1280 / 10:20 am – 5:00 pm
= 1280 / 17 hours 20 minutes
= 1280 x 3 / 52 = 73.84 kmph
Speed of train B = 1280 / 12:00 noon ⎯ 6:00 pm
= 1280/18 hours = 71.11 kmph
So, difference between the speed of train A and train B = 73.84 ⎯ 71.11 = 2.73 kmph

8. Option B
Total passengers in train A = 400 + 100 + 90 + 300 + 150 = 1040
Total passengers in train B = 300 + 150 + 270 + 50 + 100 = 870
So, required ratio = 1040 : 870 = 104 : 87

9. Option E
Total income of train A = (400 × 50) + (500 × 70) + (590 × 280) + (890 × 100) + (1040 × 120) = Rs.434000
Total income of train B = (300 × 120) + (450 × 100) + (620 × 280) + (670 × 70) + (770 × 50) = Rs.340000
So, required % = 434000 x 100 / 340000
= 127.64% of the total income of train B.

10. Option C
If the average speed of train A increases by 10%
then its new speed = 73.84 × 110/100
= 81.22 kmph
Time taken by train A during the journey = 1280/81.22 = 15.75 hours = 15 hours 45 minutes
The time when the train will reach its destination = 5 pm + 15 hours 45 minutes = 8:45 am

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#### Ramandeep Singh - Educator

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