Data Interpretation Practice Questions - Missing Figures Tables

In a series to provide practice question sets for Data Interpretation section, Today I am providing two practice sets.

Must read

• Complete Data Interpretation Guide (Free)

Study the given table carefully to answer the following questions.

Field Name	Shape	Side (in m)	Base (in m)	Height (in m)	Radius (in m)	Cost of flooring (in Rs. per sq. metre)	Cost of fencing (in Rs. per m)
A	Triangle		16	12		50	20
B	Rectangle	10 × 20				30	15
C	Square	15				40	18
D	Parallelogram		20	12		60	25
E	Circle				10	45	22

      1) What is the cost of flooring of A?

a) Rs.4000                   b) Rs.4600                   c) Rs.4800

d) Rs.5000                   e) Rs.4400

      2) What is the difference between the cost of fencing of C and that of B?

a) Rs.180                     b) Rs.120                     c) Rs.240

d) Rs.360                     e) Rs.480

      3) What is the ratio of the cost of flooring to that of fencing of field D?

a) 4 : 1                         b) 6 : 1                         c) 8 : 1

d) 9 : 1                         e) 5 : 1

      4) The cost of fencing of field E is approximately what percent of the cost of flooring of field C?

a) 10.5%                      b) 19.46%                    c) 18.71%

d) 15.36%                    e) 13.82%

      5) The cost of fencing of field C is what percent of the cost of fencing of field D?

a) 87.54%                    b) 67.5%                      c) 72.13%

d) 54.36%                    e) 46.5%

Study the given chart carefully and answer the following questions.

Train A

Station	Arrival time	Departure time	Distance from origin (in km)	Number of passengers boarding at each station	Fare (in Rs.)
Ahmedabad	Starting	5:00 pm	--	400	--
Vadodara	6:30 pm	6:35 pm	100	100	50
Bharuch	8:50 pm	9:00 pm	250	90	120
Mumbai	4:00 am	4:10 am	800	300	400
Pune	7:30 am	7:45 am	1050	150	500
Solapur	10:20 am	Terminates	1280	--	620

Train B

Station	Arrival time	Departure time	Distance from origin	Number of passengers boarding at each station	Fare (in Rs.)
Solapur	Starting	6:00 pm	--	300	--
Pune	7:40 pm	7:45 pm	230	150	120
Mumbai	9:30 pm	9:35 pm	480	270	220
Bharuch	5:40 am	5:55 am	1030	50	500
Vadodara	9:00 am	9:10 am	1180	100	570
Ahmedabad	12:00 noon	Terminates	1280	--	620

      6) The number of passengers boarding Train A at Vadodara is what percent of the number of passengers boarding Train B at Mumbai?

a) 37.03%                    b) 47.03%                                c) 27.03%

d) 47.30%                    e) None of these

      7) What is the difference between the speed of Train A and that of Train B?

a) 2.73 kmph               b) 1.97 kmph                           c) 3.6 kmph

d) 2.62 kmph               e) 3.9 kmph

      8) What is the ratio of the total passengers of Train A to that of Train B?

a) 102 : 79                   b) 104 : 87                               c) 103 : 87

d) 110 : 79                   e) 113 : 87

      9) The total income of Train A is what percent of the total income of Train B?

a) 180%                       b) 159.51%                              c) 123.29%

d) 125%                       e) 127.64%

     10) If the average speed of Train A increases by 10% then when will it reach to its destination?

a) 7:45 am                   b) 9:45 am                               c) 8:45 am

d) 10:45 am                 e) 11:45 am

Solutions

1. Option C

A is a triangle
So, area of A = 1/2 × 16 × 12 = 96 sqm
So, cost of flooring of A = 96 × 50 = Rs.4800

2. Option A

Perimeter of B = 2 (10 + 20) = 60 m
So, cost of fencing of B = 60 × 15 = 900
Perimeter of C = 4 × 15 = 60 m
So, cost of fencing of C = 60 × 18 = Rs.1080
So, required difference = 1080 ⎯ 900 = Rs.180

3. Option D
Area of D = Base × Height
= 20 × 12 = 240 mtr sq
So, cost of flooring of D= 240 × 60 = Rs.14400
Perimeter of D = 2 (20 + 12) = 64 m
So, cost of fencing of D = 64 × 25 = Rs.1600
So, required ratio = 14400 : 1600 = 9 : 1

4. Option D
Perimeter of E = 2πr = 2 × 22/7 × 10 = 440/7 m
Cost of fencing of E = 440/7 × 22 = Rs.1382.85
Area of C = 15 * 15= 225 mtr square
So, cost of flooring of C = 225 × 40 = Rs.9000
So, required % = 1382.85 x 100 / 9000
= 15.36% of flooring cost of C.

5. Option B
Fencing cost of C = Rs.1080
Fencing cost of D = Rs.1600
Required % = 1080/1600 × 100 = 67.5%

6. Option A
Required percentage = 100/270 × 100 = 37.03%

7. Option A
Speed of Train A = 1280 / 10:20 am – 5:00 pm

= 1280 / 17 hours 20 minutes
= 1280 x 3 / 52 = 73.84 kmph
Speed of train B = 1280 / 12:00 noon ⎯ 6:00 pm
= 1280/18 hours = 71.11 kmph
So, difference between the speed of train A and train B = 73.84 ⎯ 71.11 = 2.73 kmph

8. Option B
Total passengers in train A = 400 + 100 + 90 + 300 + 150 = 1040
Total passengers in train B = 300 + 150 + 270 + 50 + 100 = 870
So, required ratio = 1040 : 870 = 104 : 87

9. Option E
Total income of train A = (400 × 50) + (500 × 70) + (590 × 280) + (890 × 100) + (1040 × 120) = Rs.434000
Total income of train B = (300 × 120) + (450 × 100) + (620 × 280) + (670 × 70) + (770 × 50) = Rs.340000
So, required % = 434000 x 100 / 340000
= 127.64% of the total income of train B.

10. Option C
If the average speed of train A increases by 10%
then its new speed = 73.84 × 110/100
= 81.22 kmph
Time taken by train A during the journey = 1280/81.22 = 15.75 hours = 15 hours 45 minutes
The time when the train will reach its destination = 5 pm + 15 hours 45 minutes = 8:45 am