# Calendars : 10 Expected Questions for the Exams

#### Ques 1.

Find the day of the week on 17th July, 1776.
Ans 1.
17th July 1776 means : 1775 years + 6 months  + 17 days .
⇒   1600 years ( 400 x 4 years ) contain 0 odd days. 100 years contain 5 odd days.
⇒   75 years = 18 leap years  + 57 ordinary years = ( 18 x 2 ) + (57 x 1 ) odd days i.e. 93 odd days or 2 odd  days [ 93 - 7 gives 2 as remainder]
∴  1775 year contain  0 + 5+ 2  = 7 odd days i.e. 0 odd days
Number of days from jan. 1, 1776 to July 17, 1776 are:
⇒  31 + 29 + 31 + 30 + 31 + 17 = 199 days = 3 odd days [199- 7 gives  3 as remainder ]
∴ Total Number of odd days corresponding to the given date = 0 + 3 = 3 odd days.
⇒   Hence, the day on 17th July 1776 was Wednesday.

#### Ques 2.

What was the day on 10th November,1581 ?
Ans 2. 10th November,1581  means : 1580 years + 10 months + 10 days.
⇒  1200 years ( 400 x 3 years ) contain 0 odd days. 300 years contain 1 odd day.
⇒  80 years = 20 leap years  + 60 ordinary years  = ( 20 x 2) + 60 x 1) odd days i.e. 100 odd days or 2 odd days .
∴   1580 years contain 0 + 1 + 2 = 3 odd days.
Number of days from jan. 1, 1581 to Nov. 10, 1581 are:
⇒  31 + 28 + 31 + 30  + 31 + 30 + 31 + 31 + 30 + 31 + 10 = 314 days = 6 odd days.
∴   Total number of odd days corresponding  to the given date = 3 + 6 = 9 odd days i.e.2 odd days
⇒  Hence, the day on 10th November ,1581 was Tuesday.

#### Ques 3.

Today is Friday. What day will it be after 62 days ?
Ans 3. Each day to the week is repeated after 7 days.
∴    After 63 days ,it would be Friday.
⇒    So after 62 days, it would be Thursday.

#### Ques 4.

The First Republic Day of India was celebrate on 26th January . 1950.What was the day on that date?
Ans 4. 1600 years have 0 odd days.300 years have 1 odd day.
⇒    49 years contain 12 leap years and 37 ordinary years and therefore ( 24 + 37) odd days i.e. 5 odd days.
∴    1949 years contain (0 + 1 + 5) or 6 odd days.
⇒    26 days of January contain 5 odd days.
⇒    Total odd days = ( 6 + 5) = 11 or 4 odd days.
⇒    So the day was Thursday.

#### Ques 5.

Fine the calendar which is identical to the year 1998.
Ans 5.  We have to count the number of days from 1998 onwards  to get 0 odd days or the sum of the days divisible by 7.
Year  :    1998        1999         2000       2001      2002      2003    =  7 odd days
Number of odd days   :       1             1                2             1            1            1
The year 2004 will have the same calendar as that of 1998.

#### Ques 6.

On 1st January ,1986 it was Wednesday.The day of the week on 1st january . 1987 was
(a) Tuesday
(b) Wednesday
(c) Thursday
(d) None of these
Ans 6. Thursday
Hint : The year 1986 has one odd  day.

#### Ques 7.

If it was Saturday on December 17, 1982, what was the day on September 22, 1984 ?
(a) Sunday
(b) Monday
(c) Friday
(d) Saturday
Ans 7. Saturday
Hint : Total number of  odd days between Sep. 22, 1984 and Dec. 17 ,1982 = 0 odd days
Hence, Sep. 22, 1984  was also Saturday.

#### Ques 8.

It was Monday on 4th April, 1988.What was the day on 3rd November 1987?
(a) Monday
(b) Sunday
(c) Tuesday
(d) Wednesday
Ans 8.  Tuesday
Hint : Total number of odd days between Nov. 3,1987 and Apr. 4, 1988 = 6 odd days.
⇒    Let the  odd number associated with the day on 3rd Nov., 1987 be x.
∴    x + 6 = 1   =>  x = 2  odd days  i.e. it was Tuesday .

#### Ques 9.

The day on 5th March of a year is the same day on which date of the same year ?
(a) 5th August
(b) 5th October
(c) 5th November
(d) 5th December
Ans 9.  5th November
Hint : Take the given choices one by one . #### What's trending in BankExamsToday

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