# Quadratic Equations with Solution for SBI PO 2016 In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer

1) if x > y
2) if x < y
3) if x ≥ y
4) if x ≤ y
5) if x = y or relation cannot be established between 'x' and 'y'.

Before going to attempt these questions

#### Ques 1.

7X² – 33X + 20 = 0 ; 7Y² –+9Y -10 = 0
Solution :

==> 7X²-28X-5X+20=0
==>X=28/7 ; 5/7 = 4 ; 5/7

==>7Y²+14Y-5Y-10=0
==>Y= -14/7 ; 5/7 = -2 ; 5/7

Ans : x ≥ y

#### Ques 2.

X² = 289 ; Y  = (2197)^1/3
Solution :

==> X = +/- 17
==>Y = +13

Ans : x = y or relation cannot be established between 'x' and 'y'.

#### Ques 3.

6X² -49X+99= 0 ;   5Y²+17Y+14= 0
Solution :

==> 6X²-27X-22X+99=0
==> X = 27/6 ; 22/3 = 11/3 ; 9/2

==>5Y²+10Y+7Y+14=0
==> Y = -10/5 ; -7/5

Ans : x > y

#### Ques 4.

5X² -52X+96= 0 ;   5Y²+3Y-36= 0
Solution :

==> 5X²-40X-12X+96=0
==>X = 40/5 ; 12/5 = 8 ; 12/5

==> 5Y²+15Y-12Y-36=0
==> Y = -15/3 ; 12/5 = -3 ; 12/5

Ans : x ≥ y

#### Ques 5.

X² +10X+21= 0 ;   Y²+2Y-8= 0
Solution :

==> X² +7X+3X+21=0
==> X = -7 ; -3

==> Y²+4Y-2Y-8=0
==> Y = -4 ; 2

Ans : x = y or relation cannot be established between 'x' and 'y'.

#### Ques 6.

8X² -11X+3= 0 ;   Y²-8Y+7=0= 0
Solution :

==> 8X²-8X-3X+3=0
==> X = 8/8 ; 3/8 = 1 ; 1/8

==> Y²--7Y-Y+7=0
==> Y = 1 ; 7

Ans : x ≤ y #### What's trending in BankExamsToday

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