### Question 1:

**A person saves every year 10% of his income , if his income increases every year by 5% then his savings increase every year by ?**

__Quantity I:__**The salary of a worker is first increased by 50% and afterwards reduced by 50%.What is net change in his salary ?**

__Quantity II:__(a) quantity I > quantity II

(b) quantity I < quantity II

(c) quantity I ≥ quantity II

(c) quantity I ≥ quantity II

(d) quantity I ≤ quantity II

(e) quantity I =quantity II or relation cannot be determined

(a) quantity I < quantity II

(e) quantity I =quantity II or relation cannot be determined

### Question 2:

**‘A” invests Rs. 6000 for 12 months in a business , how much ‘B’ should invest in order that the profit after 1 year may be divided into the ratio of 2:3 ?**__Quantity I:__**Three partners invest Rs. 3000 , Rs.3500 and Rs. 1500 in a business. They divide Rs. 1200 as a profit. What is the share of the second partner?**__Quantity II:__(a) quantity I < quantity II

(b)quantity I > quantity II

(c) quantity I ≤ quantity II

(c) quantity I ≤ quantity II

(d)quantity I ≥ quantity II

(e) quantity I =quantity II or relation cannot be determined

(e) quantity I =quantity II or relation cannot be determined

### Question 3:

**Ten years ago A was half of B in age. If the ratio of their present ages is2:#.waht will be the total of their present ages ?**__Quantity I:__**The sum of the ages of a father and a son is 60 years. Also, 5 years ago , the fathers age was 9 times the age of the son .The present age of the father is ?**__Quantity II:__(a) quantity I < quantity II

(b)quantity I > quantity II

(c) quantity I ≤ quantity II (d)quantity I ≥ quantity II

(e) quantity I =quantity II or relation cannot be determined

(c) quantity I ≤ quantity II (d)quantity I ≥ quantity II

(e) quantity I =quantity II or relation cannot be determined

### Question 4:

**1 man or 2 women or 3 boys can do a piece of work in 88 days .1 man , 1woman and 1boy will do it in ?**__Quantity I:__**A and B can do a piece of work in 18 days .B and C together can do it in24 days. If A is twice as good a work man as C , find in what time B alone can do it ?**__Quantity II:__
(a) quantity I < quantity II

(b) quantity I ≤ quantity II

(c) quantity I > quantity II

(c) quantity I > quantity II

(d) quantity I ≥ quantity II

(e) quantity I =quantity II or relation cannot be determined

(e) quantity I =quantity II or relation cannot be determined

### Question 5:

**A trader lists his article at 15% above cost price and allows a discount of 5% on cash payment. Find his profit per cent.**__Quantity I:__**A dealer marks his goods 25% above the cost price. He then allows some discount on it and makes a profit of 10%. Find the rate of discount.**__Quantity II:__
(a) quantity I < quantity II

(b)quantity I > quantity II

(c) quantity I ≤ quantity II

(c) quantity I ≤ quantity II

(d)quantity I ≥ quantity II

(e) quantity I =quantity II or relation cannot be determined

(e) quantity I =quantity II or relation cannot be determined

## Solution

#### Solution (1)

Quantity I:
let the income in any year be x

So that saving for that year be 10% of x

New income = 105% x

New saving = 10% of 105% of x = 10.5% of x

Increase = 0.5% of x

Quantity II

So that saving for that year be 10% of x

New income = 105% x

New saving = 10% of 105% of x = 10.5% of x

Increase = 0.5% of x

Quantity II

Percentage increase = 0.5 / 10 * 100 % = 5%

A decrease of 50 % of 50 = 25%

A decrease of 50 % of 50 = 25%

**Hence (b) quantity II > quantity I**#### Solution (2)

Quantity I
6000 * 12 / (x * 12 ) = 2/3

24x = 216000

X= Rs. 9000

Quantity II

24x = 216000

X= Rs. 9000

Quantity II

3000:3500 :1500

i.e. 6: 7: 3

share of second partner = 7/16 *1200 =Rs,.525

So quantity I > quantity II.

i.e. 6: 7: 3

share of second partner = 7/16 *1200 =Rs,.525

So quantity I > quantity II.

**Hence (b) is the right answer**

#### Solution (3)

Quantity I:
Let A’s age 10 years ago = x years

Then B’s age 10 years ago = 2x years

According to the question

X+10 / 2x +10 = 2/3

3 (x+10 ) = 2(2x + 10)

3x +30 = 4x + 20

X= 10

Total of their present ages = x+10 +2x+10 = 50

Quantity II : F+S = 60 ……… ( 1)

F -5 = 9(S-5)

F-5 = 9S-45

F-9S = -40………. (2)

Then B’s age 10 years ago = 2x years

According to the question

X+10 / 2x +10 = 2/3

3 (x+10 ) = 2(2x + 10)

3x +30 = 4x + 20

X= 10

Total of their present ages = x+10 +2x+10 = 50

Quantity II : F+S = 60 ……… ( 1)

F -5 = 9(S-5)

F-5 = 9S-45

F-9S = -40………. (2)

SUB (1) AND (2) , WE GET

10S = 100

S = 10

Age of father = 60 – S = 50 Years

10S = 100

S = 10

Age of father = 60 – S = 50 Years

**Hence (e) is the correct answer**#### Solution (4)

Quantity I:
1man = 2 women = 3 boys

1 woman = ½ man

1 boy = 1/3 man

1man + 1 woman +1boy

= 1+1/2 + 1/3 = 11/6 men

Now, 1 man do the work in 88 days

11/6 men can do it in 88 days * 6/11= 48 days

Quantity II:

1 woman = ½ man

1 boy = 1/3 man

1man + 1 woman +1boy

= 1+1/2 + 1/3 = 11/6 men

Now, 1 man do the work in 88 days

11/6 men can do it in 88 days * 6/11= 48 days

Quantity II:

A’s 1 day work = C’s one day work

(A+B )’s 1 day work = (B’s one day work ) + C ‘s one day work

(or)

(B’s 1days work ) + (C’s 1 day work ) = 1/18

But (B’s 1 days work ) + (C’s 1days work ) = 1/24

C’s 1day’s work = 1/18 – 1/24 = 1/72

B’s one day work will be 1/ 36

####

Quantity I:

(A+B )’s 1 day work = (B’s one day work ) + C ‘s one day work

(or)

(B’s 1days work ) + (C’s 1 day work ) = 1/18

But (B’s 1 days work ) + (C’s 1days work ) = 1/24

C’s 1day’s work = 1/18 – 1/24 = 1/72

B’s one day work will be 1/ 36

**Hence B**alone can finish the work in 36days**ANSWER: (c )**So quantity I > quantity II####

Solution (5)

Quantity I:
Let the CP be rs.100

Then MP = 115 and d = 5%

SP = 100-d% / 100 * MP

SP = 10925

Profit per cent = 9.25%

Quantity II: Let the CP be Rs.100 Then MP = 125

And SP = (110 /100 * 100 )

Rate of discount = (15/125*100 ) % = 12%

Then MP = 115 and d = 5%

SP = 100-d% / 100 * MP

SP = 10925

Profit per cent = 9.25%

Quantity II: Let the CP be Rs.100 Then MP = 125

And SP = (110 /100 * 100 )

Rate of discount = (15/125*100 ) % = 12%

**Hence (a) quantity II > quantity I**