# Simplification Techniques and Tricks - PDF

Simplification is one of the most important part of Quantitative Aptitude section of any competitive exam. Today I am sharing all the techniques to solve Simplification questions quickly.

Rules of Simplification
V → Vinculum
B → Remove Brackets - in the order ( ) , { }, [ ]
O → Of
D → Division
M → Multiplication
S → Subtraction

### Important Parts of Simplification

• Number System
• HCF & LCM
• Square & Cube
• Fractions & Decimals
• Surds & Indices

### Number System

• Classification
• Divisibility Test
• Division& Remainder Rules
• Sum Rules

#### Classification

Types Description
Natural Numbers:
all counting numbers ( 1,2,3,4,5....∞)
Whole Numbers:
natural number + zero( 0,1,2,3,4,5...∞)
Integers:
All whole numbers including Negative number + Positive number(∞......-4,-3,-2,-1,0,1,2,3,4,5....∞)
Even & Odd Numbers :
All whole number divisible by 2 is Even (0,2,4,6,8,10,12.....∞) and which does not divide by 2 are Odd (1,3,5,7,9,11,13,15,17,19....∞)
Prime Numbers:
It can be positive or negative except 1, if the number is not divisible by any number except the number itself.(2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61....∞)
Composite Numbers:
Natural numbers which are not prime
Co-Prime:
Two natural number a and b are said to be co-prime if their HCF is 1.

#### Divisibility

Numbers IF A Number Examples
Divisible by 2 End with 0,2,4,6,8 are divisible by 2 254,326,3546,4718 all are divisible by 2
Divisible by 3 Sum of its digits  is divisible by 3 375,4251,78123 all are divisible by 3.  [549=5+4+9][5+4+9=18]18 is divisible by 3  hence 549 is divisible by 3.
Divisible by 4 Last two digit divisible by 4 5648 here last 2 digits are 48 which is divisible by 4 hence 5648 is also divisible by 4.
Divisible by 5 Ends with 0 or 5 225 or 330 here last digit digit is 0 or 5 that mean both the numbers are divisible by 5.
Divisible by 6 Divides by Both 2 & 3 4536 here last digit is 6 so it divisible by 2 & sum of its digit (like 4+5+3+6=18) is 18 which is divisible by 3.Hence 4536 is divisible by 6.
Divisible by 8 Last 3 digit divide by 8 746848 here last 3 digit 848 is divisible by 8 hence 746848 is also divisible by 8.
Divisible by 10 End with 0 220,450,1450,8450 all numbers has a last digit zero it means all are divisible by 10.
Divisible by 11 [Sum of its digit in
odd places-Sum of its digits
in even places]= 0 or multiple of 11
Consider the number 39798847
(Sum of its digits at odd places)-(Sum of its digits at even places)(7+8+9+9)-(4+8+7+3)
(23-12)
23-12=11, which is divisible by 11. So 39798847 is divisible by 11.

#### Division & Remainder Rules

Suppose we divide 45 by 6

hence ,represent it as:
dividend = ( divisorquotient ) + remainder
or
divisior= [(dividend)-(remainder] / quotient
could be write it as
x = kq + r where (x = dividend,k = divisor,q = quotient,r = remainder)

Example:
On dividing a certain number by 342, we get 47 as remainder. If the same number is divided by 18, what will be the remainder ?
Number = 342k + 47
( 18 19k ) + ( 18 2 ) + 11
18 ( 19k + 2 ) +11.
Remainder = 11

#### Sum Rules

(1+2+3+.........+n) = 1/n(n+1)
(12+22+32+.........+n2) = 1/n (n+1) (2n+1)
(13+23+33+.........+n3) = 1/4 n2 (n+1)2
Arithmetic Progression (A.P.)
a, a + d, a + 2d, a + 3d, ....are said to be in A.P. in which first term = a and common difference = d.
Let the nth term be tn and last term = l, then
a) nth term = a + ( n - 1 ) d
b) Sum of n terms = n/2 [2a + (n-1)d]
c) Sum of n terms = n/2 (a+l) where l is the last term

### H.C.F. & L.C.M.

• Factorization & Division Method
• HCF & LCM of Fractions & Decimal Fractions

#### Methods

On Basis
H.C.F. or G.C.M
L.C.M.
Factorization Method
Write  each number as the product of the prime factors. The product of least powers of common prime factors gives H.C.F.
Example:
Find the H.C.F. of 108, 288 and 360.
108 = 22✘33, 288 = 25✘32 and 360 = 23✘5✘32
H.C.F. = 22✘32=36
Write each numbers into a product
of prime factors. Then, L.C.M is
the product of highest powers of
all the factors.
Examples:
Find the L.C.M. of 72, 108 and 2100.
72=23✘32,108=33✘22,
2100=22✘52✘3✘7.
L.C.M.=23✘33✘52✘7=37800
Division Method
Let we have two numbers .Pick the smaller one and divide it by the larger one. After that divide the divisor with the remainder. This process of dividing the preceding number by the remainder will repeated until we got the zero  as remainder.The last divisor is the required H.C.F.
Example:

H.C.F. of given numbers = 69
Let we have set of numbers.
First of all find the number
which divide at least two of
the number in a given set of
number.remainder and
not divisible numbers
will carry forward as it is.
Repeat the process till
at least  two number is
not divisible by any number
except 1.The product of
the divisor and the
undivided numbers is the required
L.C.M.
Example:
Find the L.C.M. of 12,36,48,72
H.C.F. & L.C.M. of Fractions
H.C.F. =  H.C.F. of Numerator / L.C.M. of Denominators L.C.M. = L.C.M. of Numerator / H.C.F. of Denominators
Product of H.C.F. & L.C.M.
H.C.F * L.C.M. = product of two numbers
Decimal numbers H.C.F. of Decimal numbers
Step 1. Find the HCF of the given
numbers without decimal.
Step 2.Put the decimal point ( in the
HCF of Step 1) from right to left
according to the MAXIMUM
deciaml places among the given numbers.
L.C.M. of Decimal numbers
Step 1. Find the LCM of the given
numbers without decimal.
Step 2.Put the decimal point ( in the
LCM of Step 1) from right to left
according to the MINIMUM
deciaml places among the given numbers.

### Square & Cube

• Square & Cube
• Square Root & Cube Root
• Factorization Method
 Perfect Square Non-Perfect Square last digit is 1, 4, 9, 6, 5 last digit is 2, 3, 7, 8

Square Root & Cube Root

### Fractions & Decimals

On Basis Explanation
Decimal Fractions
A number with a denominator of power of 10 is a decimal fractions.
1/10= 1 tenth; 1/100= 0.1;38/100=0.38
Vulgar Fractions
Conversion of 0.64(decimal number) into a Vulgar Fraction.First of all write the numeric digit 1 in the denominator of a number (like here 0.64) and add as many numeric zeros as the digit in the number after decimal point.After that removes the decimal point from the given number.At last step just reduce the fraction to its lowest terms. So, 0.64 = 64/100=16/25;25.025 = 25025/1000 = 1001/4
To perform the addition and subtraction of a decimal fraction could be done through placing them right under each other that the decimal points lie in one column.
3.424+3.28+.4036+6.2+.8+4
3. 424
3. 28
. 4036
6. 2
. 8
+4______
18. 1076

Multiplication of a Decimal Fraction
To find the multiplication of decimal fraction , first of all you need to remove the decimal point from the given numbers and then perform the multiplication after that assign the decimal point as many places after the number as the sum of the number of the decimal places in the given number.
Step 1. 0.06*0.3*0.40
Step 2. 6*3*40=720
Step 3. 0.00720
Multiplication of a decimal fraction by power of 10
A multiplication of a decimal fraction by a power of 10 can be perform through shifting the decimal point towards right as many places as is the power of 10.
like 45.6288*100=45628.8, 0.00452*100=0.452
Division

Comparison of Fractions To compare the set of fractions numbers,first of all you need to convert each fraction number or value into a equal decimal value and then it will be became easy for you to assign them ( the numbers or value) in a particular way( ascending or descending order).
3/5,4/7,8/9 and 9/11 Arranging in Ascending Order
3/5= 0.6, 4/7 = 0.571, 8/9 = 0.88, 9/11 = 0.818.
Now, 0.88 > 0.818 > 0.6 > 0.571
8/9>9/11>3/5>4/7
Recurring Decimal Recurring Decimal
A decimal number in which after a decimal point a number or set of number are repeated again and again are called recurring decimal numbers.It can be written in shorten form by placing a bar or line above the numbers which has repeated.
Pure Recurring Decimal
A decimal number in which all digits are repeated after a decimal point.

Mixed Recurring Decimal
A decimal number in which certain digits are repeated only.

### Surds & Indices

• Some Rules of Indices
• Some Rules of Surds

### Simplification Shortcuts PDF

Number of pages - 46
File format - PDF
Price - Free
File-size - 750 KB

Smart Prep Kit for Banking Exams by Ramandeep Singh - Download here

### Oliveboard Test Series(Recommended)

#### Bank Exams Today Notes

1. Sir check divisible by 4/ 5642

2. 2nd mistake Dividend=divisor×quotient+reminder

3. typo error! edited ! (5648)

4. thanks SIr

5. i like it

6. SUDIPTA CHATTERJEEJuly 3, 2015 at 7:18 PM

Thanks Raman Sir.. for share .. Very helpful for me

7. Sir some shortcuts for quadratic inequalities. ..??

8. Lined up for Monday

9. Ok sir

10. Good Work, Sir !!

11. Mohd. Rizwan AliJuly 3, 2015 at 7:56 PM

Excellent work .

12. Rashmi Singh ChaudharyJuly 3, 2015 at 9:18 PM

thank u sir

13. how many months current affairs should we prepare for upcoming ibps po exam ? also could u plz provide the study plan for ibps po also

14. Durgadatta mohantyJuly 3, 2015 at 10:02 PM

thank u sir

15. Thank you sir

16. sir pls provide trick for syllogysm(possibility cases ) y vendiegram method

thnx

18. Useful for aspirants. Good job. Continue.

19. Good work.....Thanks alot

20. thanks

21. Thank you sir... Pls provide model question paper for RRB

22. Thank u sir

23. I am indebted to you.

24. Sir could you please explain in detail the sitting arrangement problem?

25. Sagar ChandrakarJuly 5, 2015 at 9:18 AM

Thanks sir

26. Sagar ChandrakarJuly 5, 2015 at 9:33 AM

Very nice sir

27. thank u sir

28. can you explain me how to find cube root and square root

29. can you explain how to find square root and cue root

30. find square root of 39204

31. Square root & cube root
http://www.bankexamstoday.com/2015/06/tricks-to-find-square-root-and-cube.html
Cube root
http://www.bankexamstoday.com/2015/06/short-tricks-to-find-cube-root.html

32. 39204
Trick for finding square root of perfect number:
Step I. last digit ends with 4 . hence possible square no. could be end with 2 or 4
( 2*2=04; 8*8=64,here last digit is 4 ;hence could be 2 or 8)

Step II. Pick first three digit 392 & find nearest square digit which smallest to 392 [ now 19*19=361 & 20*20=400 , hence square of 19 which 361 is smaller than 392) hence pick 19.
Step III. add zero . 190
Step IV. now compare . square of 19 is nearest value of 392 . so compare 361 with 392 to check whether 392 is smaller or greater. now here 392 is greater hence from step 1 pick large value which is 8.
Result or Answer or Solution is 198.

When you understand this concept you will do this in 2 step.
Actually it is a two step method ,i just explained you in detail.

Thanks for commenting. It's very difficult to answer every query here, it's better to post your query on IBPSToday.com